x=25x^2+30x+5

Solution for x=25x^2+30x+5 equation:

x=25x^2+30x+5

We move all terms to the left:

x-(25x^2+30x+5)=0

We get rid of parentheses

-25x^2+x-30x-5=0

We add all the numbers together, and all the variables

-25x^2-29x-5=0

a = -25; b = -29; c = -5;
Δ = b2-4ac
Δ = -292-4·(-25)·(-5)
Δ = 341
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-29)-\sqrt{341}}{2*-25}=\frac{29-\sqrt{341}}{-50}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-29)+\sqrt{341}}{2*-25}=\frac{29+\sqrt{341}}{-50}
$